Ragnar --

I think the construct that is most like you are looking for would be 
to type the following into a workspace and execute them with a "cmd 
(or alt) d":

foo _ 'hello'.
bar _ 'world'.
baz _ { foo. bar}.

If you then type

baz

and execute this with a "print it" -- a "cmd (or alt) d", then you will see

#('hello' 'world')

But the suggestion below will also work. The construct:

baz _ Array with: foo with: bar

will put the very same Array structure into baz, and you can see this 
by executing:

baz

with a "cmd (or alt) d"

Cheers,

Alan

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At 3:28 PM +0200 7/25/02, Ragnar Hojland Espinosa wrote:
>On Thu, Jul 25, 2002 at 07:22:03AM -0500, Martin McClure wrote:
>>  At 1:42 PM +0200 7/25/02, Ragnar Hojland Espinosa wrote:
>>  >foo _ 'hello'.
>>  >bar _ 'world!'.
>>  >baz _ #(foo bar).
>>  >
>>  >I can get the name of the var by a (baz at: 1), but how do i get its value?
>>
>>  The construct "#(foo bar)" specifies a literal Array that contains
>>  two literally-specified Symbols, #foo and #bar. It does not reference
>>  any variables.
>>
>>  One way to get what you're looking for is
>>
>>  baz _ Array with: foo with: bar.
>
>Uhh, i dont see how.. please elaborate a bit.  The following would work, but
>it saves nothing.
>
>baz _ at: 'foo' put: foo.
>baz _ at: 'bar' put: bar.
>
>
>--
>Ragnar Hojland - Project Manager
>Linalco "Especialistas Linux y en Software Libre"
>Tel: +34-91-5970074 Fax: +34-91-5970083


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