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<TITLE>RE: [BUG]Collection>>removeAll:</TITLE>
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<P><FONT SIZE=2>Hello.</FONT>
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<P><FONT SIZE=2>> 2. Designers writing the simplest clearest code they can for operations but not thinking about all the boundary cases. (x-x and x+x are perfectly reasonable in arithmetic; x\x and xUx are perfectly reasonable in set theory; but they are a sort of boundary case.)</FONT></P>
<P><FONT SIZE=2>x\x and xUx are not equivalent to removeAll: and addAll: because \ and U don't mutate the contents of x.</FONT>
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<P><FONT SIZE=2>The operation \ would correspond to copyWithoutAll:, while U would correspond to copyWithAll:.</FONT>
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<P><FONT SIZE=2>Andres.</FONT>
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