[Vm-dev] Primitive to crop a ByteArray?
Mariano Martinez Peck
marianopeck at gmail.com
Thu Nov 8 15:48:27 UTC 2012
On Thu, Nov 8, 2012 at 4:38 PM, Bert Freudenberg <bert at freudenbergs.de> wrote:
> On 2012-11-08, at 16:22, Mariano Martinez Peck <marianopeck at gmail.com> wrote:
>> Hi guys. I have the following scenario. I have a buffer (ByteArray)
>> that I pass by FFI to a function of size N. This function puts data in
>> the array and answers me the M number of bytes that it put. M <= N.
>> Finally, I need to copy the array of size N to the accuare size M.
>> To do that, I am using #copyFrom:to:. If the ByteArray is large (which
>> could be the case), this function takes significant time because it
>> needs to allocate space for the new large resulting array. So...is
>> there a destructive primitive where I can "crop" the existing array,
>> modify its size field and mark the remaining bytes as "free space for
>> the heap".
>> Do we have a primitive for that?
> We do not have any primitive that changes an object's size.
> However, if your problem is indeed the time for allocating the new array, then maybe there should be a primitive for that? E.g. one that copies a portion of one array to a new object. This would avoid having to initialize the memory of the new array - this is what's taking time, otherwise allocation is normally constant in time.
> OTOH it seems unusual that you would have to use extremely large buffers where initialization time matters. E.g. if you were to use this for reading from a file or stream then it might make more sense to use many smaller buffers rather than a single huge one, no?
Hi Bert. I should have explained better. The library I am wrapping is
LZ4, a fast compressor: http://code.google.com/p/lz4/
The function to compress looks like this:
int LZ4_compress (const char* source, char* dest, int isize);
Compresses 'isize' bytes from 'source' into 'dest'.
Destination buffer must be already allocated,
and must be sized to handle worst cases situations (input data not
Worst case size evaluation is provided by macro LZ4_compressBound()
isize : is the input size. Max supported value is ~1.9GB
return : the number of bytes written in buffer dest
So, from the image side, I am doing (summarized):
dest := ByteArray new: (self funcCompressBound: aByteArray size) + 4.
bytesCompressedOrError := self funcCompress: aByteArray
byteArrayDestination: dest isize: aByteArray size maxOutputSize:
compressed := dest copyFrom: 1 to: bytesCompressedOrError + 4.
But a normal scenario of compression is when the bytearray is indeed
quite large. The function requires that "dest" is already allocated.
And then I need to do the #copyFrom:to:, and that is what I was trying
> - Bert -
More information about the Vm-dev