There is no problem here, just put your space before the period, as in:

a:=$ .
a asciiValue

For which I, btw, get 32, which http://www.lookuptables.com/ 
corroborates is the ascii value for the space character :-)

Daniel

karl wrote:
> Bob.Cowdery at CGI-Europe.com wrote:
> 
>> I'm trying to figure out not just a way to do various string 
>> manipulations but the right way as it's pretty basic stuff. Apart from 
>> taking substrings and concatenating them is there a way to remove 
>> characters from a string.
>>
>>  
>>
>> e.g. I have a string '3.669' and I want to remove the '.'
>>
>> In a workspace I can type '3.669' replaceAll: $. with: $ and then 
>> print it and it works provided there is nothing after the second $. 
>> However in a method if I put a dot after the last $ as a terminator it 
>> takes it as a character and wants another dot for the terminator. I 
>> tried it in a block and still can't get away without putting a dot 
>> after the $. Is there some way to express this or am I barking up the 
>> wrong tree again.
>>
>>  
>>
> If you try to inspect the result instead of printing it you will get a 
> inspector in the result string.
> The you click on the second entry you will get that characters value eg. 
> 30.
> Then you can replace the $ with a Character value:30 and you get:
> '3.669' replaceAll: $. with: (Character value:30)
> 
> Karl
> 
>