Those comments helped me:

> You can parse "z = 1 + 2" multiple ways:
> 	(z = 1) + 2
> or
> 	z = (1 + 2)


>> The main reason why its occurs is when you write something like this:
>>
>> Expression:
>>   FixedPattern
>> | FixedPattern Expression
>>
>> this will force parser to shift and to grow its stack.

It was not clear to me.

My grammar contains something like:
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Expression :
		
	   Id "=" Expression			{SPAssignment new name: '1'; expression: '3'}
	   | Conditional				{'1'}
	   | VariableDefinition		{SPVariableDefinition new name: '1'}
	   | BinaryOp				{'1'}
	   | Term					{'1'}
	   ;
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=

The conflict disappeared.
Thanks for you help Mathieu

Alexandre


On 24 Apr 2007, at 10:43, Mathieu Suen wrote:

>>> The main reason why its occurs is when you write something like  
>>> this:
>>>
>>> Expression:
>>>   FixedPattern
>>> | FixedPattern Expression
>>>
>>> this will force parser to shift and to grow its stack.

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Alexandre Bergel  http://www.software-artist.eu
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