i am currently using HTTPSocket to pull data from a url...
looks like this:
| data | data := String fromByteArray: (HTTPSocket httpGet: anUrl).
i end up with a string that has my desired data (a JSON string), but, it's preceeded by this:
'a RWBinaryOrTextStream ' '<here is the stuff i need>' ' '
i am trying to lop off the first part by doing:
jsonData := dataString replaceAll: 'RWBinaryOrTextStream' with: 'test'.
just to see if i can touch the string..
but no matter what i do, i can't get any parts of the string to be raplaced..
it almost looks like there are three strings in there..
the RWBinaryOrTextStream one, the one i need, and an empty one..
is there a better way to pull a url?
thanks!
Hi Sergio,
2010/3/24 sergio_101 sergiolist@village-buzz.com
i am currently using HTTPSocket to pull data from a url...
looks like this:
| data | data := String fromByteArray: (HTTPSocket httpGet: anUrl).
the problem here is that HTTPSocket httpGet: '' return a RWBinaryOrTextStream.
To get the string, you need to send the message contents to the stream.
(HTTPSocket httpGet: 'json url') contents
i end up with a string that has my desired data (a JSON string), but, it's preceeded by this:
yes because it's a stream, not a string.
hth,
Cédrick
'a RWBinaryOrTextStream ' '<here is the stuff i need>' ' '
i am trying to lop off the first part by doing:
jsonData := dataString replaceAll: 'RWBinaryOrTextStream' with: 'test'.
just to see if i can touch the string..
but no matter what i do, i can't get any parts of the string to be raplaced..
it almost looks like there are three strings in there..
the RWBinaryOrTextStream one, the one i need, and an empty one..
is there a better way to pull a url?
thanks!
--
peace, sergio photographer, journalist, visionary
http://www.coffee-black.com http://www.painlessfrugality.com http://www.twitter.com/sergio_101 http://www.facebook.com/sergio101 _______________________________________________ Beginners mailing list Beginners@lists.squeakfoundation.org http://lists.squeakfoundation.org/mailman/listinfo/beginners
the problem here is that HTTPSocket httpGet: '' return a RWBinaryOrTextStream. To get the string, you need to send the message contents to the stream. (HTTPSocket httpGet: 'json url') contents
thanks!
just getting back to this..
my question is.. how do i know what part of the stream to look at? as in, how would i know that contents is the part i am interested in?
thanks!
oh.. and i am reading the docs about streams again...
thanks again!
the problem here is that HTTPSocket httpGet: '' return a RWBinaryOrTextStream. To get the string, you need to send the message contents to the stream. (HTTPSocket httpGet: 'json url') contents
thanks!
just getting back to this..
my question is.. how do i know what part of the stream to look at? as in, how would i know that contents is the part i am interested in?
thanks!
oh.. and i am reading the docs about streams again...
thanks again!
Not sure I understand... :)
A stream encapsulates a collection and provide facilities to navigate forward, backward, etc... (strings are collection - direct string manipulation aren't efficient)... So you use a stream to manipulate efficiently your string, and to get the string back (or whatever collection that was associated to the string), you send the message #contents.
If you se the class comment of Stream "I am an abstract class that represents an accessor for a sequence of objects. This sequence is referred to as my "contents"."
hth,
--
peace, sergio photographer, journalist, visionary
http://www.coffee-black.com http://www.painlessfrugality.com http://www.twitter.com/sergio_101 http://www.facebook.com/sergio101 _______________________________________________ Beginners mailing list Beginners@lists.squeakfoundation.org http://lists.squeakfoundation.org/mailman/listinfo/beginners
(HTTPSocket httpGet: aUrl) contents
I know we Smalltalkers like to talk about how no one ever gets confused about dynamic types, but it does happen ;-).
The stream has the text you want. May want to familiarize yourself with core methods on the Stream hierarchy.
Pushing the Stream through a ByteArray conversion is invoking printString.
Your trouble with getting a modified string using replaceAll: is again a subtle typing error:
Reading the comment for #replaceAll:with: "Replace all occurences of oldObject with newObject"
But, Strings are collections of characters, not strings. Compare:
'foo' replaceAll: 'f' with: 'g' 'foo' replaceAll: $f with: $g
Take a look at senders of #findString:
Many of them do replacements of substrings.
David Mitchell http://www.withaguide.com
On Wed, Mar 24, 2010 at 12:44 AM, sergio_101 sergiolist@village-buzz.comwrote:
i am currently using HTTPSocket to pull data from a url...
looks like this:
| data | data := String fromByteArray: (HTTPSocket httpGet: anUrl).i end up with a string that has my desired data (a JSON string), but, it's preceeded by this:
'a RWBinaryOrTextStream ' '<here is the stuff i need>' ' '
i am trying to lop off the first part by doing:
jsonData := dataString replaceAll: 'RWBinaryOrTextStream' with: 'test'.
just to see if i can touch the string..
but no matter what i do, i can't get any parts of the string to be raplaced..
it almost looks like there are three strings in there..
the RWBinaryOrTextStream one, the one i need, and an empty one..
is there a better way to pull a url?
thanks!
--
peace, sergio photographer, journalist, visionary
http://www.coffee-black.com http://www.painlessfrugality.com http://www.twitter.com/sergio_101 http://www.facebook.com/sergio101 _______________________________________________ Beginners mailing list Beginners@lists.squeakfoundation.org http://lists.squeakfoundation.org/mailman/listinfo/beginners
beginners@lists.squeakfoundation.org
-
Cédrick Béler -
David Mitchell -
sergio_101